Trailing zeros in 272 factorial = 66
Quick Answer:
66 trailing zeros in 272!
Legendre's Formula: Count factors of 5 in 272!
⌊272/5⌋ = 54 + ⌊272/25⌋ = 10 + ⌊272/125⌋ = 2 = 66
Factorial Calculator Until 10,000
Nearby Factorials
| n | n! | Digits | Trailing Zeros |
|---|---|---|---|
| 267! | 34226400...0000 | 534 | 65 |
| 268! | 91726753...0000 | 536 | 65 |
| 269! | 24674496...0000 | 539 | 65 |
| 270! | 66621141...0000 | 541 | 66 |
| 271! | 18054329...0000 | 544 | 66 |
| 272! | 49107775...0000 | 546 | 66 |
| 273! | 13406422...0000 | 549 | 66 |
| 274! | 36733598...0000 | 551 | 66 |
| 275! | 10101739...0000 | 554 | 68 |
| 276! | 27880801...0000 | 556 | 68 |
| 277! | 77229818...0000 | 558 | 68 |
Here you can find answers to questions like: What is the number of zeros on the end of 272 factorial What is the factorial of 272? What is the last digits of factorial of 272? How many trailing zeros in 272 factorial? How many digits are there in 272 factorial? Use the factorial calculator above to find the factorial of any natural between 0 and 10,000.
What is factorial?
Definition of factorial
The factorial is a quantity defined for any integer n greater than or equal to 0.
The factorial is the product of all integers less than or equal to n but greater than or equal to 1. The factorial value of 0 is, by definition, equal to 1. For negative integers, factorials are not defined. The factorial can be seen as the result of multiplying a sequence of descending natural numbers (such as 3 × 2 × 1).
The factorial symbol is the exclamation mark (!).
The factorial formula
If n is a natural number greater than or equal to 1, then
n! = n x (n - 1) x (n - 2) x (n - 3) ... 3 x 2 x 1
If n = 0, then n! = 1, by convention.
Example: 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720
Shortcut to find trailing zeros in a factorial
Trailing zeros are a sequence of zeros in the decimal representation of a number, after which no other digits follow. This video shows how to find the trailing zeros of a factorial easily.
Table of factorials until 30
| n | n! | |
|---|---|---|
| 1! | 1 | # |
| 2! | 2 | # |
| 3! | 6 | # |
| 4! | 24 | # |
| 5! | 120 | # |
| 6! | 720 | # |
| 7! | 5040 | # |
| 8! | 40320 | # |
| 9! | 362880 | # |
| 10! | 3628800 | # |
| 11! | 39916800 | # |
| 12! | 479001600 | # |
| 13! | 6227020800 | # |
| 14! | 87178291200 | # |
| 15! | 1307674368000 | # |
| 16! | 20922789888000 | # |
| 17! | 355687428096000 | # |
| 18! | 6402373705728000 | # |
| 19! | 121645100408832000 | # |
| 20! | 2432902008176640000 | # |
| 21! | 51090942171709440000 | # |
| 22! | 1124000727777607680000 | # |
| 23! | 25852016738884976640000 | # |
| 24! | 620448401733239439360000 | # |
| 25! | 15511210043330985984000000 | # |
| 26! | 403291461126605635584000000 | # |
| 27! | 10888869450418352160768000000 | # |
| 28! | 304888344611713860501504000000 | # |
| 29! | 8841761993739701954543616000000 | # |
| 30! | 265252859812191058636308480000000 | # |
Frequently Asked Questions
How many trailing zeros are in 272 factorial?
There are 66 trailing zeros in 272!. This is calculated using Legendre's formula: count how many times 5 divides into 272, then 25, then 125, and so on, adding up all the quotients.
What is Legendre's formula?
Legendre's formula calculates the number of trailing zeros in n! by summing ⌊n/5⌋ + ⌊n/25⌋ + ⌊n/125⌋ + ... until the quotient becomes 0. Each trailing zero comes from a factor of 10, which requires one factor of 2 and one factor of 5.
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