Is -216 a Perfect Cube? Yes — ∛(-216) = -6

Quick Answer

Yes, -216 is a perfect cube.  ∛(-216) = -6.

Because (-6) × (-6) × (-6) = -216.  (Unlike squares, negatives can be perfect cubes.)

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Verdict
Yes — ∛(-216) = -6

Use the checker above to determine whether any integer is a perfect cube. A perfect cube is an integer of the form for some integer k. Unlike perfect squares, perfect cubes can be negative: since (-k)³ = -k³, every negative integer whose absolute value is a perfect cube is itself a perfect cube. The first non-negative perfect cubes are 0, 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, ...

Step-by-Step: Why -216 Is a Perfect Cube

  1. Write -216 as -(216).
  2. ∛216 = 6, so ∛(-216) = -6.
  3. Verify: (-6) × (-6) × (-6) = -216 ✓
  4. Unlike perfect squares, negative integers can be perfect cubes because the cube of a negative is negative.
  5. Prime factorization check (of |n| = 216):
    216 = 23 × 33
    All exponents are divisible by 3 ⇒ 216 is a perfect cube.

∛(-216) = -6

What Is a Perfect Cube?

A perfect cube is an integer that is the cube of an integer:

n is a perfect cube  ⇔  n = k3,  k ∈ ℤ

Equivalently, n is a perfect cube if and only if ∛n is an integer. Geometrically, you can arrange n identical unit cubes into a cubic grid only if n is a non-negative perfect cube.

Signs: Unlike perfect squares (which are always non-negative), perfect cubes can be negative. Examples of negative perfect cubes: -1 = (-1)³, -8 = (-2)³, -27 = (-3)³, -64 = (-4)³, -125 = (-5)³.

Prime-factorization rule: |n| is a perfect cube iff every prime in its prime factorization appears with an exponent divisible by 3. For example, 216 = 23 × 33 (both divisible by 3) is a perfect cube; 72 = 23 × 32 has exponent 2 on 3, so it is not.

Nearby Examples

nIs perfect?∛n or nearest
128No125 < 128 < 216
125Yes∛125 = 5
100No64 < 100 < 125
343Yes∛343 = 7
72No64 < 72 < 125
64Yes∛64 = 4
27Yes∛27 = 3
24No8 < 24 < 27

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