Is 768 a Perfect Cube? No

Quick Answer

No, 768 is not a perfect cube. Nearest are 729 (9³) and 1000 (10³).

∛768 ≈ 9.1577, which is not an integer.

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Verdict
No

Use the checker above to determine whether any integer is a perfect cube. A perfect cube is an integer of the form for some integer k. Unlike perfect squares, perfect cubes can be negative: since (-k)³ = -k³, every negative integer whose absolute value is a perfect cube is itself a perfect cube. The first non-negative perfect cubes are 0, 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, ...

Step-by-Step: Why 768 Is Not a Perfect Cube

  1. Try ∛768 ≈ 9.1577  (not an integer).
  2. Prime factorization of |n| = 768:
    768 = 28 × 3
  3. The exponent of 2 is 8not divisible by 3. A number is a perfect cube if and only if every prime in its factorization has an exponent divisible by 3, so 768 cannot be written as k³.
  4. Nearest perfect cubes:
    • 729 = 9³  (just below)
    • 1000 = 10³  (just above)

What Is a Perfect Cube?

A perfect cube is an integer that is the cube of an integer:

n is a perfect cube  ⇔  n = k3,  k ∈ ℤ

Equivalently, n is a perfect cube if and only if ∛n is an integer. Geometrically, you can arrange n identical unit cubes into a cubic grid only if n is a non-negative perfect cube.

Signs: Unlike perfect squares (which are always non-negative), perfect cubes can be negative. Examples of negative perfect cubes: -1 = (-1)³, -8 = (-2)³, -27 = (-3)³, -64 = (-4)³, -125 = (-5)³.

Prime-factorization rule: |n| is a perfect cube iff every prime in its prime factorization appears with an exponent divisible by 3. For example, 216 = 23 × 33 (both divisible by 3) is a perfect cube; 72 = 23 × 32 has exponent 2 on 3, so it is not.

Nearby Examples

nIs perfect?∛n or nearest
729Yes∛729 = 9
1000Yes∛1000 = 10
512Yes∛512 = 8
343Yes∛343 = 7
216Yes∛216 = 6
1331Yes∛1331 = 11
128No125 < 128 < 216
125Yes∛125 = 5

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