0.5 Cups of Capers to Pounds Conversion

Question:
How many pounds of capers in 0.5 US cups? How much is 0.5 cups of capers in pounds?

The answer is:
0.5 US cups of capers is equivalent to 0.132 ( ~ ¹/₄) pounds^(*)

Volume to 'Weight' Converter

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Results: 0.5 US cups of capers equals 0.132 ( ~ ¹/₄) pounds. (*)
(*) To be more precise, 0.5 US cups of capers is equal to 0.13222 pounds. All figures are approximate.

Website Map

US cups of capers to pounds Chart

US cups of capers to pounds
0.41 US cups of capers	=	0.108 pounds
0.42 US cups of capers	=	0.111 pounds
0.43 US cups of capers	=	0.114 pounds
0.44 US cups of capers	=	0.116 pounds
0.45 US cups of capers	=	0.119 pounds
0.46 US cups of capers	=	0.122 pounds
0.47 US cups of capers	=	0.124 pounds
0.48 US cups of capers	=	0.127 pounds
0.49 US cups of capers	=	0.13 pounds
¹/₂ US cups of capers	=	0.132 pounds

US cups of capers to pounds
¹/₂ US cups of capers	=	0.132 pounds
0.51 US cups of capers	=	0.135 pounds
0.52 US cups of capers	=	0.138 pounds
0.53 US cups of capers	=	0.14 pounds
0.54 US cups of capers	=	0.143 pounds
0.55 US cups of capers	=	0.145 pounds
0.56 US cups of capers	=	0.148 pounds
0.57 US cups of capers	=	0.151 pounds
0.58 US cups of capers	=	0.153 pounds
0.59 US cups of capers	=	0.156 pounds

Note: some values may be rounded.

FAQs on capers weight to volume conversion

0.5 US cups of capers equals how many pounds?

0.5 US cups of capers is equivalent 0.132 ( ~ ¹/₄) pounds.

How much is 0.132 pounds of capers in US cups?

0.132 pounds of capers equals 0.5 ( ~ ¹/₂) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.