0.5 Cup of Dried Beans to Pounds Conversion

Question:
How many pounds of dried beans in 0.5 US cup? How much is 0.5 cup of dried beans in pounds?

The answer is:
0.5 US cup of dried beans is equivalent to 0.198 ( ~ 1/4) pound(*)

Volume to 'Weight' Converter

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Results:

0.5 US cup of dried beans equals 0.198 ( ~ 1/4) pound. (*)
(*) To be more precise, 0.5 US cup of dried beans is equal to 0.19846 pound. All figures are approximate.

US cups of dried beans to pounds Chart

US cups of dried beans to pounds
0.41 US cup of dried beans = 0.163 pound
0.42 US cup of dried beans = 0.167 pound
0.43 US cup of dried beans = 0.171 pound
0.44 US cup of dried beans = 0.175 pound
0.45 US cup of dried beans = 0.179 pound
0.46 US cup of dried beans = 0.183 pound
0.47 US cup of dried beans = 0.187 pound
0.48 US cup of dried beans = 0.191 pound
0.49 US cup of dried beans = 0.194 pound
1/2 US cup of dried beans = 0.198 pound
US cups of dried beans to pounds
1/2 US cup of dried beans = 0.198 pound
0.51 US cup of dried beans = 0.202 pound
0.52 US cup of dried beans = 0.206 pound
0.53 US cup of dried beans = 0.21 pound
0.54 US cup of dried beans = 0.214 pound
0.55 US cup of dried beans = 0.218 pound
0.56 US cup of dried beans = 0.222 pound
0.57 US cup of dried beans = 0.226 pound
0.58 US cup of dried beans = 0.23 pound
0.59 US cup of dried beans = 0.234 pound

Note: some values may be rounded.

FAQs on dried beans weight to volume conversion

0.5 US cup of dried beans equals how many pounds?

0.5 US cup of dried beans is equivalent 0.198 ( ~ 1/4) pound.

How much is 0.198 pound of dried beans in US cups?

0.198 pound of dried beans equals 0.5 ( ~ 1/2) US cup.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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