1/4 Cups of Semolina to Pounds Conversion

Question:
How many pounds of semolina in 1/4 US cups? How much is 1/4 cups of semolina in pounds?

The answer is:
1/4 US cups of semolina is equivalent to 0.0992 pounds^(*)

Volume to 'Weight' Converter

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Results: 1/4 US cups of semolina equals 0.0992 pounds. (*)
(*) To be more precise, 1/4 US cups of semolina is equal to 0.099232 pounds. All figures are approximate.

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US cups of semolina to pounds Chart

US cups of semolina to pounds
0.16 US cups of semolina	=	0.0635 pounds
0.17 US cups of semolina	=	0.0675 pounds
0.18 US cups of semolina	=	0.0714 pounds
0.19 US cups of semolina	=	0.0754 pounds
¹/₅ US cups of semolina	=	0.0794 pounds
0.21 US cups of semolina	=	0.0834 pounds
0.22 US cups of semolina	=	0.0873 pounds
0.23 US cups of semolina	=	0.0913 pounds
0.24 US cups of semolina	=	0.0953 pounds
¹/₄ US cups of semolina	=	0.0992 pounds

US cups of semolina to pounds
¹/₄ US cups of semolina	=	0.0992 pounds
0.26 US cups of semolina	=	0.103 pounds
0.27 US cups of semolina	=	0.107 pounds
0.28 US cups of semolina	=	0.111 pounds
0.29 US cups of semolina	=	0.115 pounds
0.3 US cups of semolina	=	0.119 pounds
0.31 US cups of semolina	=	0.123 pounds
0.32 US cups of semolina	=	0.127 pounds
0.33 US cups of semolina	=	0.131 pounds
0.34 US cups of semolina	=	0.135 pounds

Note: some values may be rounded.

FAQs on semolina weight to volume conversion

1/4 US cups of semolina equals how many pounds?

1/4 US cups of semolina is equivalent 0.0992 pounds.

How much is 0.0992 pounds of semolina in US cups?

0.0992 pounds of semolina equals 1/4 ( ~ ¹/₄) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.