1 Ml of Cocoa to Kg Conversion

Question:
How many kilograms of cocoa in 1 milliliter? How much is 1 ml of cocoa in kg?

The answer is:
1 milliliter of cocoa is equivalent to 0.000528 kilogram(*)

Volume to 'Weight' Converter

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Results:

1 milliliter of cocoa equals 0.000528 kilogram. (*)
(*) To be more precise, 1 milliliter of cocoa is equal to 0.000528 kilogram. All figures are approximate.

Milliliters of cocoa to kilograms Chart

Milliliters of cocoa to kilograms
0.1 milliliter of cocoa = 5.28 × 10-5 kilogram
1/5 milliliter of cocoa = 0.000106 kilogram
0.3 milliliter of cocoa = 0.000158 kilogram
0.4 milliliter of cocoa = 0.000211 kilogram
1/2 milliliter of cocoa = 0.000264 kilogram
0.6 milliliter of cocoa = 0.000317 kilogram
0.7 milliliter of cocoa = 0.00037 kilogram
0.8 milliliter of cocoa = 0.000422 kilogram
0.9 milliliter of cocoa = 0.000475 kilogram
1 milliliter of cocoa = 0.000528 kilogram
Milliliters of cocoa to kilograms
1 milliliter of cocoa = 0.000528 kilogram
1.1 milliliter of cocoa = 0.000581 kilogram
1/5 milliliter of cocoa = 0.000634 kilogram
1.3 milliliter of cocoa = 0.000686 kilogram
1.4 milliliter of cocoa = 0.000739 kilogram
1/2 milliliter of cocoa = 0.000792 kilogram
1.6 milliliter of cocoa = 0.000845 kilogram
1.7 milliliter of cocoa = 0.000898 kilogram
1.8 milliliter of cocoa = 0.00095 kilogram
1.9 milliliter of cocoa = 0.001 kilogram

Note: some values may be rounded.

FAQs on cocoa weight to volume conversion

1 milliliter of cocoa equals how many kilograms?

1 milliliter of cocoa is equivalent 0.000528 kilogram.

How much is 0.000528 kilogram of cocoa in milliliters?

0.000528 kilogram of cocoa equals 1 milliliter.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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