1 Ml of Cocoa to Pounds Conversion

Question:
How many pounds of cocoa in 1 milliliter? How much is 1 ml of cocoa in pounds?

The answer is:
1 milliliter of cocoa is equivalent to 0.00116 pound(*)

Volume to 'Weight' Converter

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Results:

1 milliliter of cocoa equals 0.00116 pound. (*)
(*) To be more precise, 1 milliliter of cocoa is equal to 0.001164 pound. All figures are approximate.

Milliliters of cocoa to pounds Chart

Milliliters of cocoa to pounds
0.1 milliliter of cocoa = 0.000116 pound
1/5 milliliter of cocoa = 0.000233 pound
0.3 milliliter of cocoa = 0.000349 pound
0.4 milliliter of cocoa = 0.000466 pound
1/2 milliliter of cocoa = 0.000582 pound
0.6 milliliter of cocoa = 0.000698 pound
0.7 milliliter of cocoa = 0.000815 pound
0.8 milliliter of cocoa = 0.000931 pound
0.9 milliliter of cocoa = 0.00105 pound
1 milliliter of cocoa = 0.00116 pound
Milliliters of cocoa to pounds
1 milliliter of cocoa = 0.00116 pound
1.1 milliliter of cocoa = 0.00128 pound
1 1/5 milliliter of cocoa = 0.0014 pound
1.3 milliliter of cocoa = 0.00151 pound
1.4 milliliter of cocoa = 0.00163 pound
1 1/2 milliliter of cocoa = 0.00175 pound
1.6 milliliter of cocoa = 0.00186 pound
1.7 milliliter of cocoa = 0.00198 pound
1.8 milliliter of cocoa = 0.0021 pound
1.9 milliliter of cocoa = 0.00221 pound

Note: some values may be rounded.

FAQs on cocoa weight to volume conversion

1 milliliter of cocoa equals how many pounds?

1 milliliter of cocoa is equivalent 0.00116 pound.

How much is 0.00116 pound of cocoa in milliliters?

0.00116 pound of cocoa equals 1 milliliter.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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