1 Ml of Cocoa Powder to Grams Conversion

Question:
How many grams of cocoa powder in 1 milliliter? How much is 1 ml of cocoa powder in grams?

The answer is:
1 milliliter of cocoa powder is equivalent to 0.507 gram(*)

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Results:

1 milliliter of cocoa powder equals 0.507 gram. (*)
(*) To be more precise, 1 milliliter of cocoa powder is equal to 0.507 gram. All figures are approximate.

Milliliters of cocoa powder to grams Chart

Milliliters of cocoa powder to grams
0.1 milliliter of cocoa powder = 0.0507 gram
1/5 milliliter of cocoa powder = 0.101 gram
0.3 milliliter of cocoa powder = 0.152 gram
0.4 milliliter of cocoa powder = 0.203 gram
1/2 milliliter of cocoa powder = 0.254 gram
0.6 milliliter of cocoa powder = 0.304 gram
0.7 milliliter of cocoa powder = 0.355 gram
0.8 milliliter of cocoa powder = 0.406 gram
0.9 milliliter of cocoa powder = 0.456 gram
1 milliliter of cocoa powder = 0.507 gram
Milliliters of cocoa powder to grams
1 milliliter of cocoa powder = 0.507 gram
1.1 milliliter of cocoa powder = 0.558 gram
1/5 milliliter of cocoa powder = 0.608 gram
1.3 milliliter of cocoa powder = 0.659 gram
1.4 milliliter of cocoa powder = 0.71 gram
1/2 milliliter of cocoa powder = 0.761 gram
1.6 milliliter of cocoa powder = 0.811 gram
1.7 milliliter of cocoa powder = 0.862 gram
1.8 milliliter of cocoa powder = 0.913 gram
1.9 milliliter of cocoa powder = 0.963 gram

Note: some values may be rounded.

FAQs on cocoa powder weight to volume conversion

1 milliliter of cocoa powder equals how many grams?

1 milliliter of cocoa powder is equivalent 0.507 gram.

How much is 0.507 gram of cocoa powder in milliliters?

0.507 gram of cocoa powder equals 1 milliliter.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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