1 Ml of Cream to Pounds Conversion

Question:
How many pounds of cream in 1 milliliter? How much is 1 ml of cream in pounds?

The answer is:
1 milliliter of cream is equivalent to 0.00224 pound(*)

Volume to 'Weight' Converter

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Results:

1 milliliter of cream equals 0.00224 pound. (*)
(*) To be more precise, 1 milliliter of cream is equal to 0.0022355 pound. All figures are approximate.

Milliliters of cream to pounds Chart

Milliliters of cream to pounds
0.1 milliliter of cream = 0.000224 pound
1/5 milliliter of cream = 0.000447 pound
0.3 milliliter of cream = 0.000671 pound
0.4 milliliter of cream = 0.000894 pound
1/2 milliliter of cream = 0.00112 pound
0.6 milliliter of cream = 0.00134 pound
0.7 milliliter of cream = 0.00156 pound
0.8 milliliter of cream = 0.00179 pound
0.9 milliliter of cream = 0.00201 pound
1 milliliter of cream = 0.00224 pound
Milliliters of cream to pounds
1 milliliter of cream = 0.00224 pound
1.1 milliliter of cream = 0.00246 pound
1 1/5 milliliter of cream = 0.00268 pound
1.3 milliliter of cream = 0.00291 pound
1.4 milliliter of cream = 0.00313 pound
1 1/2 milliliter of cream = 0.00335 pound
1.6 milliliter of cream = 0.00358 pound
1.7 milliliter of cream = 0.0038 pound
1.8 milliliter of cream = 0.00402 pound
1.9 milliliter of cream = 0.00425 pound

Note: some values may be rounded.

FAQs on cream weight to volume conversion

1 milliliter of cream equals how many pounds?

1 milliliter of cream is equivalent 0.00224 pound.

How much is 0.00224 pound of cream in milliliters?

0.00224 pound of cream equals 1 milliliter.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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