1 Ml of Dry Lentils to Grams Conversion

Question:
How many grams of dry lentils in 1 milliliter? How much is 1 ml of dry lentils in grams?

The answer is:
1 milliliter of dry lentils is equivalent to 0.845 grams(*)

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Results:

1 milliliter of dry lentils equals 0.845 grams. (*)
(*) To be more precise, 1 milliliter of dry lentils is equal to 0.845 grams. All figures are approximate.

Milliliters of dry lentils to grams Chart

Milliliters of dry lentils to grams
0.1 milliliters of dry lentils = 0.0845 grams
1/5 milliliters of dry lentils = 0.169 grams
0.3 milliliters of dry lentils = 0.254 grams
0.4 milliliters of dry lentils = 0.338 grams
1/2 milliliters of dry lentils = 0.423 grams
0.6 milliliters of dry lentils = 0.507 grams
0.7 milliliters of dry lentils = 0.592 grams
0.8 milliliters of dry lentils = 0.676 grams
0.9 milliliters of dry lentils = 0.761 grams
1 milliliter of dry lentils = 0.845 grams
Milliliters of dry lentils to grams
1 milliliter of dry lentils = 0.845 grams
1.1 milliliters of dry lentils = 0.93 grams
1/5 milliliters of dry lentils = 1.01 grams
1.3 milliliters of dry lentils = 1.1 grams
1.4 milliliters of dry lentils = 1.18 grams
1/2 milliliters of dry lentils = 1.27 grams
1.6 milliliters of dry lentils = 1.35 grams
1.7 milliliters of dry lentils = 1.44 grams
1.8 milliliters of dry lentils = 1.52 grams
1.9 milliliters of dry lentils = 1.61 grams

Note: some values may be rounded.

FAQs on dry lentils weight to volume conversion

1 milliliter of dry lentils equals how many grams?

1 milliliter of dry lentils is equivalent 0.845 grams.

How much is 0.845 grams of dry lentils in milliliters?

0.845 grams of dry lentils equals 1 milliliter.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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