1 1/2 Cups of Bulgur to Lb Conversion

Question:
How many pounds of bulgur in 1 1/2 US cups? How much are 1 1/2 cups of bulgur in lb?

The answer is:
1 1/2 US cups of bulgur is equivalent to 0.628 ( ~ ³/₄) pounds^(*)

Volume to 'Weight' Converter

I need to convert ...
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Results: 1 1/2 US cups of bulgur equals 0.628 ( ~ ³/₄) pounds. (*)
(*) To be more precise, 1 1/2 US cups of bulgur is equal to 0.62825 pounds. All figures are approximate.

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US cups of bulgur to pounds Chart

US cups of bulgur to pounds
0.6 US cups of bulgur	=	0.251 pounds
0.7 US cups of bulgur	=	0.293 pounds
0.8 US cups of bulgur	=	0.335 pounds
0.9 US cups of bulgur	=	0.377 pounds
1 US cup of bulgur	=	0.419 pounds
1.1 US cups of bulgur	=	0.461 pounds
1 ¹/₅ US cups of bulgur	=	0.503 pounds
1.3 US cups of bulgur	=	0.544 pounds
1.4 US cups of bulgur	=	0.586 pounds
1 ¹/₂ US cups of bulgur	=	0.628 pounds

US cups of bulgur to pounds
1 ¹/₂ US cups of bulgur	=	0.628 pounds
1.6 US cups of bulgur	=	0.67 pounds
1.7 US cups of bulgur	=	0.712 pounds
1.8 US cups of bulgur	=	0.754 pounds
1.9 US cups of bulgur	=	0.796 pounds
2 US cups of bulgur	=	0.838 pounds
2.1 US cups of bulgur	=	0.88 pounds
2 ¹/₅ US cups of bulgur	=	0.921 pounds
2.3 US cups of bulgur	=	0.963 pounds
2.4 US cups of bulgur	=	1.01 pounds

Note: some values may be rounded.

FAQs on bulgur weight to volume conversion

1 1/2 US cups of bulgur equals how many pounds?

1 1/2 US cups of bulgur is equivalent 0.628 ( ~ ³/₄) pounds.

How much is 0.628 pounds of bulgur in US cups?

0.628 pounds of bulgur equals 1 1/2 ( ~ 1 ¹/₂) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.