1 1/2 Cups of Icing Sugar to Lb Conversion

Question:
How many pounds of icing sugar in 1 1/2 US cup? How much are 1 1/2 cup of icing sugar in lb?

The answer is:
1 1/2 US cup of icing sugar is equivalent to 0.413 ( ~ 1/2) pound(*)

Volume to 'Weight' Converter

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Results:

1 1/2 US cup of icing sugar equals 0.413 ( ~ 1/2) pound. (*)
(*) To be more precise, 1 1/2 US cup of icing sugar is equal to 0.4131 pound. All figures are approximate.

US cups of icing sugar to pounds Chart

US cups of icing sugar to pounds
0.6 US cup of icing sugar = 0.165 pound
0.7 US cup of icing sugar = 0.193 pound
0.8 US cup of icing sugar = 0.22 pound
0.9 US cup of icing sugar = 0.248 pound
1 US cup of icing sugar = 0.275 pound
1.1 US cup of icing sugar = 0.303 pound
1/5 US cup of icing sugar = 0.33 pound
1.3 US cup of icing sugar = 0.358 pound
1.4 US cup of icing sugar = 0.386 pound
1/2 US cup of icing sugar = 0.413 pound
US cups of icing sugar to pounds
1/2 US cup of icing sugar = 0.413 pound
1.6 US cup of icing sugar = 0.441 pound
1.7 US cup of icing sugar = 0.468 pound
1.8 US cup of icing sugar = 0.496 pound
1.9 US cup of icing sugar = 0.523 pound
2 US cups of icing sugar = 0.551 pound
2.1 US cups of icing sugar = 0.578 pound
1/5 US cups of icing sugar = 0.606 pound
2.3 US cups of icing sugar = 0.633 pound
2.4 US cups of icing sugar = 0.661 pound

Note: some values may be rounded.

FAQs on icing sugar weight to volume conversion

1 1/2 US cup of icing sugar equals how many pounds?

1 1/2 US cup of icing sugar is equivalent 0.413 ( ~ 1/2) pound.

How much is 0.413 pound of icing sugar in US cups?

0.413 pound of icing sugar equals 1 1/2 ( ~ 1 1/2) US cup.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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