1 1/4 Cups of Baking Powder to Grams Conversion

Question:
How many grams of baking powder in 1 1/4 US cup? How much are 1 1/4 cup of baking powder in grams?

The answer is:
1 1/4 US cup of baking powder is equivalent to 287 grams(*)

Volume to 'Weight' Converter

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Results:

1 1/4 US cup of baking powder equals 287 grams. (*)
(*) To be more precise, 1 1/4 US cup of baking powder is equal to 287.45 grams. All figures are approximate.

US cups of baking powder to grams Chart

US cups of baking powder to grams
0.35 US cup of baking powder = 80.5 grams
0.45 US cup of baking powder = 103 grams
0.55 US cup of baking powder = 126 grams
0.65 US cup of baking powder = 149 grams
3/4 US cup of baking powder = 172 grams
0.85 US cup of baking powder = 195 grams
0.95 US cup of baking powder = 218 grams
1.05 US cup of baking powder = 241 grams
1.15 US cup of baking powder = 264 grams
1/4 US cup of baking powder = 287 grams
US cups of baking powder to grams
1/4 US cup of baking powder = 287 grams
1.35 US cup of baking powder = 310 grams
1.45 US cup of baking powder = 333 grams
1.55 US cup of baking powder = 356 grams
1.65 US cup of baking powder = 379 grams
3/4 US cup of baking powder = 402 grams
1.85 US cup of baking powder = 425 grams
1.95 US cup of baking powder = 448 grams
2.05 US cups of baking powder = 471 grams
2.15 US cups of baking powder = 494 grams

Note: some values may be rounded.

FAQs on baking powder weight to volume conversion

1 1/4 US cup of baking powder equals how many grams?

1 1/4 US cup of baking powder is equivalent 287 grams.

How much is 287 grams of baking powder in US cups?

287 grams of baking powder equals 1 1/4 ( ~ 1 1/4) US cup.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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