1 1/4 Cups of Spring Onion to Grams Conversion
Question:
How many grams of spring onion in 1 1/4 US cup? How much are 1 1/4 cup of spring onion in grams?
The answer is:
1 1/4 US cup of spring onion is equivalent to 130 grams(*)
Volume to 'Weight' Converter
US cups of spring onion to grams Chart
US cups of spring onion to grams | ||
---|---|---|
0.35 US cup of spring onion | = | 36.4 grams |
0.45 US cup of spring onion | = | 46.8 grams |
0.55 US cup of spring onion | = | 57.3 grams |
0.65 US cup of spring onion | = | 67.7 grams |
3/4 US cup of spring onion | = | 78.1 grams |
0.85 US cup of spring onion | = | 88.5 grams |
0.95 US cup of spring onion | = | 98.9 grams |
1.05 US cup of spring onion | = | 109 grams |
1.15 US cup of spring onion | = | 120 grams |
1 1/4 US cup of spring onion | = | 130 grams |
US cups of spring onion to grams | ||
---|---|---|
1 1/4 US cup of spring onion | = | 130 grams |
1.35 US cup of spring onion | = | 141 grams |
1.45 US cup of spring onion | = | 151 grams |
1.55 US cup of spring onion | = | 161 grams |
1.65 US cup of spring onion | = | 172 grams |
1 3/4 US cup of spring onion | = | 182 grams |
1.85 US cup of spring onion | = | 193 grams |
1.95 US cup of spring onion | = | 203 grams |
2.05 US cups of spring onion | = | 213 grams |
2.15 US cups of spring onion | = | 224 grams |
Note: some values may be rounded.
FAQs on spring onion weight to volume conversion
1 1/4 US cup of spring onion equals how many grams?
1 1/4 US cup of spring onion is equivalent 130 grams.
How much is 130 grams of spring onion in US cups?
130 grams of spring onion equals 1 1/4 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.