1 2/3 Cups of Coarse Salt to Lb Conversion
Question:
How many pounds of coarse salt in 1 2/3 US cup? How much are 1 2/3 cup of coarse salt in lb?
The answer is:
1 2/3 US cup of coarse salt is equivalent to 0.809 ( ~
Volume to 'Weight' Converter
US cups of coarse salt to pounds Chart
US cups of coarse salt to pounds | ||
---|---|---|
0.767 US cup of coarse salt | = | 0.372 pound |
0.867 US cup of coarse salt | = | 0.421 pound |
0.967 US cup of coarse salt | = | 0.469 pound |
1.067 US cup of coarse salt | = | 0.518 pound |
1.167 US cup of coarse salt | = | 0.566 pound |
1.267 US cup of coarse salt | = | 0.615 pound |
1.367 US cup of coarse salt | = | 0.663 pound |
1.467 US cup of coarse salt | = | 0.712 pound |
1.567 US cup of coarse salt | = | 0.76 pound |
1.67 US cup of coarse salt | = | 0.809 pound |
US cups of coarse salt to pounds | ||
---|---|---|
1.67 US cup of coarse salt | = | 0.809 pound |
1.767 US cup of coarse salt | = | 0.857 pound |
1.867 US cup of coarse salt | = | 0.906 pound |
1.967 US cup of coarse salt | = | 0.954 pound |
2.067 US cups of coarse salt | = | 1 pound |
2.167 US cups of coarse salt | = | 1.05 pound |
2.267 US cups of coarse salt | = | 1.1 pound |
2.367 US cups of coarse salt | = | 1.15 pound |
2.467 US cups of coarse salt | = | 1.2 pound |
2.567 US cups of coarse salt | = | 1.25 pound |
Note: some values may be rounded.
FAQs on coarse salt weight to volume conversion
1 2/3 US cup of coarse salt equals how many pounds?
1 2/3 US cup of coarse salt is equivalent 0.809 ( ~
How much is 0.809 pound of coarse salt in US cups?
0.809 pound of coarse salt equals 1 2/3 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.