1 2/3 Cups of Dry Lentils to Grams Conversion
Question:
How many grams of dry lentils in 1 2/3 US cups? How much are 1 2/3 cups of dry lentils in grams?
The answer is:
1 2/3 US cups of dry lentils is equivalent to 333 grams(*)
Volume to 'Weight' Converter
US cups of dry lentils to grams Chart
US cups of dry lentils to grams | ||
---|---|---|
0.767 US cups of dry lentils | = | 153 grams |
0.867 US cups of dry lentils | = | 173 grams |
0.967 US cups of dry lentils | = | 193 grams |
1.067 US cups of dry lentils | = | 213 grams |
1.167 US cups of dry lentils | = | 233 grams |
1.267 US cups of dry lentils | = | 253 grams |
1.367 US cups of dry lentils | = | 273 grams |
1.467 US cups of dry lentils | = | 293 grams |
1.567 US cups of dry lentils | = | 313 grams |
1.67 US cups of dry lentils | = | 333 grams |
US cups of dry lentils to grams | ||
---|---|---|
1.67 US cups of dry lentils | = | 333 grams |
1.767 US cups of dry lentils | = | 353 grams |
1.867 US cups of dry lentils | = | 373 grams |
1.967 US cups of dry lentils | = | 393 grams |
2.067 US cups of dry lentils | = | 413 grams |
2.167 US cups of dry lentils | = | 433 grams |
2.267 US cups of dry lentils | = | 453 grams |
2.367 US cups of dry lentils | = | 473 grams |
2.467 US cups of dry lentils | = | 493 grams |
2.567 US cups of dry lentils | = | 513 grams |
Note: some values may be rounded.
FAQs on dry lentils weight to volume conversion
1 2/3 US cups of dry lentils equals how many grams?
1 2/3 US cups of dry lentils is equivalent 333 grams.
How much is 333 grams of dry lentils in US cups?
333 grams of dry lentils equals 1 2/3 ( ~ 1
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.