1 2/3 Cups of Margarine to Lb Conversion

Question:
How many pounds of margarine in 1 2/3 US cups? How much are 1 2/3 cups of margarine in lb?

The answer is:
1 2/3 US cups of margarine is equivalent to 0.919 ( ~ 1) pounds(*)

Volume to 'Weight' Converter

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Results:

1 2/3 US cups of margarine equals 0.919 ( ~ 1) pounds. (*)
(*) To be more precise, 1 2/3 US cups of margarine is equal to 0.91905 pounds. All figures are approximate.

US cups of margarine to pounds Chart

US cups of margarine to pounds
0.767 US cups of margarine = 0.423 pounds
0.867 US cups of margarine = 0.478 pounds
0.967 US cups of margarine = 0.533 pounds
1.067 US cups of margarine = 0.588 pounds
1.167 US cups of margarine = 0.643 pounds
1.267 US cups of margarine = 0.699 pounds
1.367 US cups of margarine = 0.754 pounds
1.467 US cups of margarine = 0.809 pounds
1.567 US cups of margarine = 0.864 pounds
1.67 US cups of margarine = 0.919 pounds
US cups of margarine to pounds
1.67 US cups of margarine = 0.919 pounds
1.767 US cups of margarine = 0.974 pounds
1.867 US cups of margarine = 1.03 pounds
1.967 US cups of margarine = 1.08 pounds
2.067 US cups of margarine = 1.14 pounds
2.167 US cups of margarine = 1.19 pounds
2.267 US cups of margarine = 1.25 pounds
2.367 US cups of margarine = 1.3 pounds
2.467 US cups of margarine = 1.36 pounds
2.567 US cups of margarine = 1.42 pounds

Note: some values may be rounded.

FAQs on margarine weight to volume conversion

1 2/3 US cups of margarine equals how many pounds?

1 2/3 US cups of margarine is equivalent 0.919 ( ~ 1) pounds.

How much is 0.919 pounds of margarine in US cups?

0.919 pounds of margarine equals 1 2/3 ( ~ 1 3/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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