1 2/3 Cups of Polenta to Pounds Conversion

Question:
How many pounds of polenta in 1 2/3 US cup? How much are 1 2/3 cup of polenta in pounds?

The answer is:
1 2/3 US cup of polenta is equivalent to 0.588 ( ~ 1/2) pound(*)

Volume to 'Weight' Converter

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Results:

1 2/3 US cup of polenta equals 0.588 ( ~ 1/2) pound. (*)
(*) To be more precise, 1 2/3 US cup of polenta is equal to 0.58777 pound. All figures are approximate.

US cups of polenta to pounds Chart

US cups of polenta to pounds
0.767 US cup of polenta = 0.27 pound
0.867 US cup of polenta = 0.306 pound
0.967 US cup of polenta = 0.341 pound
1.067 US cup of polenta = 0.376 pound
1.167 US cup of polenta = 0.411 pound
1.267 US cup of polenta = 0.447 pound
1.367 US cup of polenta = 0.482 pound
1.467 US cup of polenta = 0.517 pound
1.567 US cup of polenta = 0.553 pound
1.67 US cup of polenta = 0.588 pound
US cups of polenta to pounds
1.67 US cup of polenta = 0.588 pound
1.767 US cup of polenta = 0.623 pound
1.867 US cup of polenta = 0.658 pound
1.967 US cup of polenta = 0.694 pound
2.067 US cups of polenta = 0.729 pound
2.167 US cups of polenta = 0.764 pound
2.267 US cups of polenta = 0.799 pound
2.367 US cups of polenta = 0.835 pound
2.467 US cups of polenta = 0.87 pound
2.567 US cups of polenta = 0.905 pound

Note: some values may be rounded.

FAQs on polenta weight to volume conversion

1 2/3 US cup of polenta equals how many pounds?

1 2/3 US cup of polenta is equivalent 0.588 ( ~ 1/2) pound.

How much is 0.588 pound of polenta in US cups?

0.588 pound of polenta equals 1 2/3 ( ~ 1 3/4) US cup.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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