10 Cups of Caster Sugar to Lb Conversion
Question:
How many pounds of caster sugar in 10 US cups? How much are 10 cups of caster sugar in lb?
The answer is:
10 US cups of caster sugar is equivalent to 4.41 ( ~ 4
Volume to 'Weight' Converter
US cups of caster sugar to pounds Chart
US cups of caster sugar to pounds | ||
---|---|---|
1 US cup of caster sugar | = | 0.441 pounds |
2 US cups of caster sugar | = | 0.881 pounds |
3 US cups of caster sugar | = | 1.32 pounds |
4 US cups of caster sugar | = | 1.76 pounds |
5 US cups of caster sugar | = | 2.2 pounds |
6 US cups of caster sugar | = | 2.64 pounds |
7 US cups of caster sugar | = | 3.09 pounds |
8 US cups of caster sugar | = | 3.53 pounds |
9 US cups of caster sugar | = | 3.97 pounds |
10 US cups of caster sugar | = | 4.41 pounds |
US cups of caster sugar to pounds | ||
---|---|---|
10 US cups of caster sugar | = | 4.41 pounds |
11 US cups of caster sugar | = | 4.85 pounds |
12 US cups of caster sugar | = | 5.29 pounds |
13 US cups of caster sugar | = | 5.73 pounds |
14 US cups of caster sugar | = | 6.17 pounds |
15 US cups of caster sugar | = | 6.61 pounds |
16 US cups of caster sugar | = | 7.05 pounds |
17 US cups of caster sugar | = | 7.49 pounds |
18 US cups of caster sugar | = | 7.93 pounds |
19 US cups of caster sugar | = | 8.37 pounds |
Note: some values may be rounded.
FAQs on caster sugar weight to volume conversion
10 US cups of caster sugar equals how many pounds?
10 US cups of caster sugar is equivalent 4.41 ( ~ 4
How much is 4.41 pounds of caster sugar in US cups?
4.41 pounds of caster sugar equals 10 ( ~ 10) US cups.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.