10 Cups of Castor Oil to Pounds Conversion
Question:
How many pounds of castor oil in 10 US cups? How much are 10 cups of castor oil in pounds?
The answer is:
10 US cups of castor oil is equivalent to 5.01 ( ~ 5) pounds(*)
Volume to 'Weight' Converter
US cups of castor oil to pounds Chart
| US cups of castor oil to pounds | ||
|---|---|---|
| 1 US cup of castor oil | = | 0.501 pounds |
| 2 US cups of castor oil | = | 1 pounds |
| 3 US cups of castor oil | = | 1.5 pounds |
| 4 US cups of castor oil | = | 2 pounds |
| 5 US cups of castor oil | = | 2.51 pounds |
| 6 US cups of castor oil | = | 3.01 pounds |
| 7 US cups of castor oil | = | 3.51 pounds |
| 8 US cups of castor oil | = | 4.01 pounds |
| 9 US cups of castor oil | = | 4.51 pounds |
| 10 US cups of castor oil | = | 5.01 pounds |
| US cups of castor oil to pounds | ||
|---|---|---|
| 10 US cups of castor oil | = | 5.01 pounds |
| 11 US cups of castor oil | = | 5.51 pounds |
| 12 US cups of castor oil | = | 6.01 pounds |
| 13 US cups of castor oil | = | 6.52 pounds |
| 14 US cups of castor oil | = | 7.02 pounds |
| 15 US cups of castor oil | = | 7.52 pounds |
| 16 US cups of castor oil | = | 8.02 pounds |
| 17 US cups of castor oil | = | 8.52 pounds |
| 18 US cups of castor oil | = | 9.02 pounds |
| 19 US cups of castor oil | = | 9.52 pounds |
Note: some values may be rounded.
FAQs on castor oil weight to volume conversion
10 US cups of castor oil equals how many pounds?
10 US cups of castor oil is equivalent 5.01 ( ~ 5) pounds.
How much is 5.01 pounds of castor oil in US cups?
5.01 pounds of castor oil equals 10 ( ~ 10) US cups.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.