10 Cups of Dry Lentils to Grams Conversion
Question:
How many grams of dry lentils in 10 US cups? How much are 10 cups of dry lentils in grams?
The answer is:
10 US cups of dry lentils is equivalent to 2000 grams(*)
Volume to 'Weight' Converter
US cups of dry lentils to grams Chart
| US cups of dry lentils to grams | ||
|---|---|---|
| 1 US cup of dry lentils | = | 200 grams |
| 2 US cups of dry lentils | = | 400 grams |
| 3 US cups of dry lentils | = | 600 grams |
| 4 US cups of dry lentils | = | 800 grams |
| 5 US cups of dry lentils | = | 1000 grams |
| 6 US cups of dry lentils | = | 1200 grams |
| 7 US cups of dry lentils | = | 1400 grams |
| 8 US cups of dry lentils | = | 1600 grams |
| 9 US cups of dry lentils | = | 1800 grams |
| 10 US cups of dry lentils | = | 2000 grams |
| US cups of dry lentils to grams | ||
|---|---|---|
| 10 US cups of dry lentils | = | 2000 grams |
| 11 US cups of dry lentils | = | 2200 grams |
| 12 US cups of dry lentils | = | 2400 grams |
| 13 US cups of dry lentils | = | 2600 grams |
| 14 US cups of dry lentils | = | 2800 grams |
| 15 US cups of dry lentils | = | 3000 grams |
| 16 US cups of dry lentils | = | 3200 grams |
| 17 US cups of dry lentils | = | 3400 grams |
| 18 US cups of dry lentils | = | 3600 grams |
| 19 US cups of dry lentils | = | 3800 grams |
Note: some values may be rounded.
FAQs on dry lentils weight to volume conversion
10 US cups of dry lentils equals how many grams?
10 US cups of dry lentils is equivalent 2000 grams.
How much is 2000 grams of dry lentils in US cups?
2000 grams of dry lentils equals 10 ( ~ 10) US cups.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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