10 Ml of Semolina to Pounds Conversion
Question:
How many pounds of semolina in 10 milliliters? How much are 10 ml of semolina in pounds?
The answer is:
10 milliliters of semolina is equivalent to 0.0168 pounds(*)
Volume to 'Weight' Converter
Milliliters of semolina to pounds Chart
Milliliters of semolina to pounds | ||
---|---|---|
1 milliliter of semolina | = | 0.00168 pounds |
2 milliliters of semolina | = | 0.00336 pounds |
3 milliliters of semolina | = | 0.00503 pounds |
4 milliliters of semolina | = | 0.00671 pounds |
5 milliliters of semolina | = | 0.00839 pounds |
6 milliliters of semolina | = | 0.0101 pounds |
7 milliliters of semolina | = | 0.0117 pounds |
8 milliliters of semolina | = | 0.0134 pounds |
9 milliliters of semolina | = | 0.0151 pounds |
10 milliliters of semolina | = | 0.0168 pounds |
Milliliters of semolina to pounds | ||
---|---|---|
10 milliliters of semolina | = | 0.0168 pounds |
11 milliliters of semolina | = | 0.0185 pounds |
12 milliliters of semolina | = | 0.0201 pounds |
13 milliliters of semolina | = | 0.0218 pounds |
14 milliliters of semolina | = | 0.0235 pounds |
15 milliliters of semolina | = | 0.0252 pounds |
16 milliliters of semolina | = | 0.0268 pounds |
17 milliliters of semolina | = | 0.0285 pounds |
18 milliliters of semolina | = | 0.0302 pounds |
19 milliliters of semolina | = | 0.0319 pounds |
Note: some values may be rounded.
FAQs on semolina weight to volume conversion
10 milliliters of semolina equals how many pounds?
10 milliliters of semolina is equivalent 0.0168 pounds.
How much is 0.0168 pounds of semolina in milliliters?
0.0168 pounds of semolina equals 10 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.