15 Ml of Polenta to Pounds Conversion
Question:
How many pounds of polenta in 15 milliliters? How much are 15 ml of polenta in pounds?
The answer is:
15 milliliters of polenta is equivalent to 0.0224 pounds(*)
Volume to 'Weight' Converter
Milliliters of polenta to pounds Chart
Milliliters of polenta to pounds | ||
---|---|---|
6 milliliters of polenta | = | 0.00894 pounds |
7 milliliters of polenta | = | 0.0104 pounds |
8 milliliters of polenta | = | 0.0119 pounds |
9 milliliters of polenta | = | 0.0134 pounds |
10 milliliters of polenta | = | 0.0149 pounds |
11 milliliters of polenta | = | 0.0164 pounds |
12 milliliters of polenta | = | 0.0179 pounds |
13 milliliters of polenta | = | 0.0194 pounds |
14 milliliters of polenta | = | 0.0209 pounds |
15 milliliters of polenta | = | 0.0224 pounds |
Milliliters of polenta to pounds | ||
---|---|---|
15 milliliters of polenta | = | 0.0224 pounds |
16 milliliters of polenta | = | 0.0238 pounds |
17 milliliters of polenta | = | 0.0253 pounds |
18 milliliters of polenta | = | 0.0268 pounds |
19 milliliters of polenta | = | 0.0283 pounds |
20 milliliters of polenta | = | 0.0298 pounds |
21 milliliters of polenta | = | 0.0313 pounds |
22 milliliters of polenta | = | 0.0328 pounds |
23 milliliters of polenta | = | 0.0343 pounds |
24 milliliters of polenta | = | 0.0358 pounds |
Note: some values may be rounded.
FAQs on polenta weight to volume conversion
15 milliliters of polenta equals how many pounds?
15 milliliters of polenta is equivalent 0.0224 pounds.
How much is 0.0224 pounds of polenta in milliliters?
0.0224 pounds of polenta equals 15 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.