16 Cups of Packed Mâche to Pounds Conversion

Question:
How many pounds of packed mâche in 16 US cups? How much are 16 cups of packed mâche in pounds?

The answer is:
16 US cups of packed mâche is equivalent to 0.709 ( ~ 3/4) pounds(*)

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Results:

16 US cups of packed mâche equals 0.709 ( ~ 3/4) pounds. (*)
(*) To be more precise, 16 US cups of packed mâche is equal to 0.70936 pounds. All figures are approximate.

US cups of packed mâche to pounds Chart

US cups of packed mâche to pounds
7 US cups of packed mâche = 0.31 pounds
8 US cups of packed mâche = 0.355 pounds
9 US cups of packed mâche = 0.399 pounds
10 US cups of packed mâche = 0.443 pounds
11 US cups of packed mâche = 0.488 pounds
12 US cups of packed mâche = 0.532 pounds
13 US cups of packed mâche = 0.576 pounds
14 US cups of packed mâche = 0.621 pounds
15 US cups of packed mâche = 0.665 pounds
16 US cups of packed mâche = 0.709 pounds
US cups of packed mâche to pounds
16 US cups of packed mâche = 0.709 pounds
17 US cups of packed mâche = 0.754 pounds
18 US cups of packed mâche = 0.798 pounds
19 US cups of packed mâche = 0.842 pounds
20 US cups of packed mâche = 0.887 pounds
21 US cups of packed mâche = 0.931 pounds
22 US cups of packed mâche = 0.975 pounds
23 US cups of packed mâche = 1.02 pounds
24 US cups of packed mâche = 1.06 pounds
25 US cups of packed mâche = 1.11 pounds

Note: some values may be rounded.

FAQs on packed mâche weight to volume conversion

16 US cups of packed mâche equals how many pounds?

16 US cups of packed mâche is equivalent 0.709 ( ~ 3/4) pounds.

How much is 0.709 pounds of packed mâche in US cups?

0.709 pounds of packed mâche equals 16 ( ~ 16) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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