16 Cups of Wheatgerm to Pounds Conversion

Question:
How many pounds of wheatgerm in 16 US cups? How much are 16 cups of wheatgerm in pounds?

The answer is:
16 US cups of wheatgerm is equivalent to 2.93 ( ~ 3) pounds(*)

Volume to 'Weight' Converter

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Results:

16 US cups of wheatgerm equals 2.93 ( ~ 3) pounds. (*)
(*) To be more precise, 16 US cups of wheatgerm is equal to 2.9292 pounds. All figures are approximate.

US cups of wheatgerm to pounds Chart

US cups of wheatgerm to pounds
7 US cups of wheatgerm = 1.28 pound
8 US cups of wheatgerm = 1.46 pound
9 US cups of wheatgerm = 1.65 pound
10 US cups of wheatgerm = 1.83 pound
11 US cups of wheatgerm = 2.01 pounds
12 US cups of wheatgerm = 2.2 pounds
13 US cups of wheatgerm = 2.38 pounds
14 US cups of wheatgerm = 2.56 pounds
15 US cups of wheatgerm = 2.75 pounds
16 US cups of wheatgerm = 2.93 pounds
US cups of wheatgerm to pounds
16 US cups of wheatgerm = 2.93 pounds
17 US cups of wheatgerm = 3.11 pounds
18 US cups of wheatgerm = 3.3 pounds
19 US cups of wheatgerm = 3.48 pounds
20 US cups of wheatgerm = 3.66 pounds
21 US cups of wheatgerm = 3.84 pounds
22 US cups of wheatgerm = 4.03 pounds
23 US cups of wheatgerm = 4.21 pounds
24 US cups of wheatgerm = 4.39 pounds
25 US cups of wheatgerm = 4.58 pounds

Note: some values may be rounded.

FAQs on wheatgerm weight to volume conversion

16 US cups of wheatgerm equals how many pounds?

16 US cups of wheatgerm is equivalent 2.93 ( ~ 3) pounds.

How much is 2.93 pounds of wheatgerm in US cups?

2.93 pounds of wheatgerm equals 16 ( ~ 16) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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