16 Tbsp of Semolina to Grams Conversion
Question:
How many grams of semolina in 16 US tablespoons? How much are 16 tbsp of semolina in grams?
The answer is:
16 US tablespoons of semolina is equivalent to 180 grams(*)
Volume to 'Weight' Converter
US tablespoons of semolina to grams Chart
US tablespoons of semolina to grams | ||
---|---|---|
7 US tablespoons of semolina | = | 78.8 grams |
8 US tablespoons of semolina | = | 90 grams |
9 US tablespoons of semolina | = | 101 grams |
10 US tablespoons of semolina | = | 113 grams |
11 US tablespoons of semolina | = | 124 grams |
12 US tablespoons of semolina | = | 135 grams |
13 US tablespoons of semolina | = | 146 grams |
14 US tablespoons of semolina | = | 158 grams |
15 US tablespoons of semolina | = | 169 grams |
16 US tablespoons of semolina | = | 180 grams |
US tablespoons of semolina to grams | ||
---|---|---|
16 US tablespoons of semolina | = | 180 grams |
17 US tablespoons of semolina | = | 191 grams |
18 US tablespoons of semolina | = | 203 grams |
19 US tablespoons of semolina | = | 214 grams |
20 US tablespoons of semolina | = | 225 grams |
21 US tablespoons of semolina | = | 236 grams |
22 US tablespoons of semolina | = | 248 grams |
23 US tablespoons of semolina | = | 259 grams |
24 US tablespoons of semolina | = | 270 grams |
25 US tablespoons of semolina | = | 281 grams |
Note: some values may be rounded.
FAQs on semolina weight to volume conversion
16 US tablespoons of semolina equals how many grams?
16 US tablespoons of semolina is equivalent 180 grams.
How much is 180 grams of semolina in US tablespoons?
180 grams of semolina equals 16 ( ~ 16) US tablespoons.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.