2/3 Teaspoon of Vinegar to Grams Conversion

Question:
How many grams of vinegar in 2/3 US teaspoon? How much is 2/3 teaspoon of vinegar in grams?

The answer is:
2/3 US teaspoon of vinegar is equivalent to 3.19 grams(*)

Volume to 'Weight' Converter

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Results:

2/3 US teaspoon of vinegar equals 3.19 grams. (*)
(*) To be more precise, 2/3 US teaspoon of vinegar is equal to 3.1941 grams. All figures are approximate.

US teaspoons of vinegar to grams Chart

US teaspoons of vinegar to grams
0.5767 US teaspoon of vinegar = 2.76 grams
0.5867 US teaspoon of vinegar = 2.81 grams
0.5967 US teaspoon of vinegar = 2.86 grams
0.6067 US teaspoon of vinegar = 2.91 grams
0.6167 US teaspoon of vinegar = 2.95 grams
0.6267 US teaspoon of vinegar = 3 grams
0.6367 US teaspoon of vinegar = 3.05 grams
0.6467 US teaspoon of vinegar = 3.1 grams
0.6567 US teaspoon of vinegar = 3.15 grams
0.667 US teaspoon of vinegar = 3.19 grams
US teaspoons of vinegar to grams
0.667 US teaspoon of vinegar = 3.19 grams
0.6767 US teaspoon of vinegar = 3.24 grams
0.6867 US teaspoon of vinegar = 3.29 grams
0.6967 US teaspoon of vinegar = 3.34 grams
0.7067 US teaspoon of vinegar = 3.39 grams
0.7167 US teaspoon of vinegar = 3.43 grams
0.7267 US teaspoon of vinegar = 3.48 grams
0.7367 US teaspoon of vinegar = 3.53 grams
0.7467 US teaspoon of vinegar = 3.58 grams
0.7567 US teaspoon of vinegar = 3.63 grams

Note: some values may be rounded.

FAQs on vinegar weight to volume conversion

2/3 US teaspoon of vinegar equals how many grams?

2/3 US teaspoon of vinegar is equivalent 3.19 grams.

How much is 3.19 grams of vinegar in US teaspoons?

3.19 grams of vinegar equals 2/3 ( ~ 3/4) US teaspoon.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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