2/3 Tsp of Semolina to Grams Conversion
Question:
How many grams of semolina in 2/3 US teaspoon? How much is 2/3 tsp of semolina in grams?
The answer is:
2/3 US teaspoon of semolina is equivalent to 2.5 grams(*)
Volume to 'Weight' Converter
US teaspoons of semolina to grams Chart
US teaspoons of semolina to grams | ||
---|---|---|
0.5767 US teaspoon of semolina | = | 2.16 grams |
0.5867 US teaspoon of semolina | = | 2.2 grams |
0.5967 US teaspoon of semolina | = | 2.24 grams |
0.6067 US teaspoon of semolina | = | 2.28 grams |
0.6167 US teaspoon of semolina | = | 2.31 grams |
0.6267 US teaspoon of semolina | = | 2.35 grams |
0.6367 US teaspoon of semolina | = | 2.39 grams |
0.6467 US teaspoon of semolina | = | 2.43 grams |
0.6567 US teaspoon of semolina | = | 2.46 grams |
0.667 US teaspoon of semolina | = | 2.5 grams |
US teaspoons of semolina to grams | ||
---|---|---|
0.667 US teaspoon of semolina | = | 2.5 grams |
0.6767 US teaspoon of semolina | = | 2.54 grams |
0.6867 US teaspoon of semolina | = | 2.58 grams |
0.6967 US teaspoon of semolina | = | 2.61 grams |
0.7067 US teaspoon of semolina | = | 2.65 grams |
0.7167 US teaspoon of semolina | = | 2.69 grams |
0.7267 US teaspoon of semolina | = | 2.73 grams |
0.7367 US teaspoon of semolina | = | 2.76 grams |
0.7467 US teaspoon of semolina | = | 2.8 grams |
0.7567 US teaspoon of semolina | = | 2.84 grams |
Note: some values may be rounded.
FAQs on semolina weight to volume conversion
2/3 US teaspoon of semolina equals how many grams?
2/3 US teaspoon of semolina is equivalent 2.5 grams.
How much is 2.5 grams of semolina in US teaspoons?
2.5 grams of semolina equals 2/3 ( ~
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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