2 Ml of Polenta to Pounds Conversion

Question:
How many pounds of polenta in 2 milliliters? How much are 2 ml of polenta in pounds?

The answer is:
2 milliliters of polenta is equivalent to 0.00298 pounds(*)

Volume to 'Weight' Converter

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Results:

2 milliliters of polenta equals 0.00298 pounds. (*)
(*) To be more precise, 2 milliliters of polenta is equal to 0.0029806 pounds. All figures are approximate.

Milliliters of polenta to pounds Chart

Milliliters of polenta to pounds
1.1 milliliters of polenta = 0.00164 pounds
1/5 milliliters of polenta = 0.00179 pounds
1.3 milliliters of polenta = 0.00194 pounds
1.4 milliliters of polenta = 0.00209 pounds
1/2 milliliters of polenta = 0.00224 pounds
1.6 milliliters of polenta = 0.00238 pounds
1.7 milliliters of polenta = 0.00253 pounds
1.8 milliliters of polenta = 0.00268 pounds
1.9 milliliters of polenta = 0.00283 pounds
2 milliliters of polenta = 0.00298 pounds
Milliliters of polenta to pounds
2 milliliters of polenta = 0.00298 pounds
2.1 milliliters of polenta = 0.00313 pounds
1/5 milliliters of polenta = 0.00328 pounds
2.3 milliliters of polenta = 0.00343 pounds
2.4 milliliters of polenta = 0.00358 pounds
1/2 milliliters of polenta = 0.00373 pounds
2.6 milliliters of polenta = 0.00387 pounds
2.7 milliliters of polenta = 0.00402 pounds
2.8 milliliters of polenta = 0.00417 pounds
2.9 milliliters of polenta = 0.00432 pounds

Note: some values may be rounded.

FAQs on polenta weight to volume conversion

2 milliliters of polenta equals how many pounds?

2 milliliters of polenta is equivalent 0.00298 pounds.

How much is 0.00298 pounds of polenta in milliliters?

0.00298 pounds of polenta equals 2 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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