2 1/2 Cups of Semolina to Lb Conversion

Question:
How many pounds of semolina in 2 1/2 US cups? How much are 2 1/2 cups of semolina in lb?

The answer is:
2 1/2 US cups of semolina is equivalent to 0.992 ( ~ 1) pounds(*)

Volume to 'Weight' Converter

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Results:

2 1/2 US cups of semolina equals 0.992 ( ~ 1) pounds. (*)
(*) To be more precise, 2 1/2 US cups of semolina is equal to 0.99232 pounds. All figures are approximate.

US cups of semolina to pounds Chart

US cups of semolina to pounds
1.6 US cups of semolina = 0.635 pounds
1.7 US cups of semolina = 0.675 pounds
1.8 US cups of semolina = 0.714 pounds
1.9 US cups of semolina = 0.754 pounds
2 US cups of semolina = 0.794 pounds
2.1 US cups of semolina = 0.834 pounds
2 1/5 US cups of semolina = 0.873 pounds
2.3 US cups of semolina = 0.913 pounds
2.4 US cups of semolina = 0.953 pounds
2 1/2 US cups of semolina = 0.992 pounds
US cups of semolina to pounds
2 1/2 US cups of semolina = 0.992 pounds
2.6 US cups of semolina = 1.03 pounds
2.7 US cups of semolina = 1.07 pounds
2.8 US cups of semolina = 1.11 pounds
2.9 US cups of semolina = 1.15 pounds
3 US cups of semolina = 1.19 pounds
3.1 US cups of semolina = 1.23 pounds
3 1/5 US cups of semolina = 1.27 pounds
3.3 US cups of semolina = 1.31 pounds
3.4 US cups of semolina = 1.35 pounds

Note: some values may be rounded.

FAQs on semolina weight to volume conversion

2 1/2 US cups of semolina equals how many pounds?

2 1/2 US cups of semolina is equivalent 0.992 ( ~ 1) pounds.

How much is 0.992 pounds of semolina in US cups?

0.992 pounds of semolina equals 2 1/2 ( ~ 2 1/2) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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