2 1/3 Cups of Bulgur to Pounds Conversion

Question:
How many pounds of bulgur in 2 1/3 US cups? How much are 2 1/3 cups of bulgur in pounds?

The answer is:
2 1/3 US cups of bulgur is equivalent to 0.977 ( ~ 1) pounds^(*)

Volume to 'Weight' Converter

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Results: 2 1/3 US cups of bulgur equals 0.977 ( ~ 1) pounds. (*)
(*) To be more precise, 2 1/3 US cups of bulgur is equal to 0.97714 pounds. All figures are approximate.

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US cups of bulgur to pounds Chart

US cups of bulgur to pounds
1.433 US cups of bulgur	=	0.6 pounds
1.533 US cups of bulgur	=	0.642 pounds
1.633 US cups of bulgur	=	0.684 pounds
1.733 US cups of bulgur	=	0.726 pounds
1.833 US cups of bulgur	=	0.768 pounds
1.933 US cups of bulgur	=	0.81 pounds
2.033 US cups of bulgur	=	0.851 pounds
2.133 US cups of bulgur	=	0.893 pounds
2.233 US cups of bulgur	=	0.935 pounds
2.33 US cups of bulgur	=	0.977 pounds

US cups of bulgur to pounds
2.33 US cups of bulgur	=	0.977 pounds
2.433 US cups of bulgur	=	1.02 pounds
2.533 US cups of bulgur	=	1.06 pounds
2.633 US cups of bulgur	=	1.1 pounds
2.733 US cups of bulgur	=	1.14 pounds
2.833 US cups of bulgur	=	1.19 pounds
2.933 US cups of bulgur	=	1.23 pounds
3.033 US cups of bulgur	=	1.27 pounds
3.133 US cups of bulgur	=	1.31 pounds
3.233 US cups of bulgur	=	1.35 pounds

Note: some values may be rounded.

FAQs on bulgur weight to volume conversion

2 1/3 US cups of bulgur equals how many pounds?

2 1/3 US cups of bulgur is equivalent 0.977 ( ~ 1) pounds.

How much is 0.977 pounds of bulgur in US cups?

0.977 pounds of bulgur equals 2 1/3 ( ~ 2 ¹/₄) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.