2 1/3 Cups of Dry Lentils to Grams Conversion
Question:
How many grams of dry lentils in 2 1/3 US cups? How much are 2 1/3 cups of dry lentils in grams?
The answer is:
2 1/3 US cups of dry lentils is equivalent to 466 grams(*)
Volume to 'Weight' Converter
US cups of dry lentils to grams Chart
US cups of dry lentils to grams | ||
---|---|---|
1.433 US cups of dry lentils | = | 286 grams |
1.533 US cups of dry lentils | = | 306 grams |
1.633 US cups of dry lentils | = | 326 grams |
1.733 US cups of dry lentils | = | 346 grams |
1.833 US cups of dry lentils | = | 366 grams |
1.933 US cups of dry lentils | = | 386 grams |
2.033 US cups of dry lentils | = | 406 grams |
2.133 US cups of dry lentils | = | 426 grams |
2.233 US cups of dry lentils | = | 446 grams |
2.33 US cups of dry lentils | = | 466 grams |
US cups of dry lentils to grams | ||
---|---|---|
2.33 US cups of dry lentils | = | 466 grams |
2.433 US cups of dry lentils | = | 486 grams |
2.533 US cups of dry lentils | = | 506 grams |
2.633 US cups of dry lentils | = | 526 grams |
2.733 US cups of dry lentils | = | 546 grams |
2.833 US cups of dry lentils | = | 566 grams |
2.933 US cups of dry lentils | = | 586 grams |
3.033 US cups of dry lentils | = | 606 grams |
3.133 US cups of dry lentils | = | 626 grams |
3.233 US cups of dry lentils | = | 646 grams |
Note: some values may be rounded.
FAQs on dry lentils weight to volume conversion
2 1/3 US cups of dry lentils equals how many grams?
2 1/3 US cups of dry lentils is equivalent 466 grams.
How much is 466 grams of dry lentils in US cups?
466 grams of dry lentils equals 2 1/3 ( ~ 2
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.