2 1/3 Cups of Mozzarella to Lb Conversion

Question:
How many pounds of mozzarella in 2 1/3 US cups? How much are 2 1/3 cups of mozzarella in lb?

The answer is:
2 1/3 US cups of mozzarella is equivalent to 1.16 ( ~ 1 1/4) pound(*)

Volume to 'Weight' Converter

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Results:

2 1/3 US cups of mozzarella equals 1.16 ( ~ 1 1/4) pound. (*)
(*) To be more precise, 2 1/3 US cups of mozzarella is equal to 1.1572 pound. All figures are approximate.

US cups of mozzarella to pounds Chart

US cups of mozzarella to pounds
1.433 US cup of mozzarella = 0.711 pound
1.533 US cup of mozzarella = 0.76 pound
1.633 US cup of mozzarella = 0.81 pound
1.733 US cup of mozzarella = 0.86 pound
1.833 US cup of mozzarella = 0.909 pound
1.933 US cup of mozzarella = 0.959 pound
2.033 US cups of mozzarella = 1.01 pound
2.133 US cups of mozzarella = 1.06 pound
2.233 US cups of mozzarella = 1.11 pound
2.33 US cups of mozzarella = 1.16 pound
US cups of mozzarella to pounds
2.33 US cups of mozzarella = 1.16 pound
2.433 US cups of mozzarella = 1.21 pound
2.533 US cups of mozzarella = 1.26 pound
2.633 US cups of mozzarella = 1.31 pound
2.733 US cups of mozzarella = 1.36 pound
2.833 US cups of mozzarella = 1.41 pound
2.933 US cups of mozzarella = 1.45 pound
3.033 US cups of mozzarella = 1.5 pound
3.133 US cups of mozzarella = 1.55 pound
3.233 US cups of mozzarella = 1.6 pound

Note: some values may be rounded.

FAQs on mozzarella weight to volume conversion

2 1/3 US cups of mozzarella equals how many pounds?

2 1/3 US cups of mozzarella is equivalent 1.16 ( ~ 1 1/4) pound.

How much is 1.16 pound of mozzarella in US cups?

1.16 pound of mozzarella equals 2 1/3 ( ~ 2 1/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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