2 1/3 Cups of Semolina to Lb Conversion

Question:
How many pounds of semolina in 2 1/3 US cups? How much are 2 1/3 cups of semolina in lb?

The answer is:
2 1/3 US cups of semolina is equivalent to 0.926 ( ~ 1) pound(*)

Volume to 'Weight' Converter

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Results:

2 1/3 US cups of semolina equals 0.926 ( ~ 1) pound. (*)
(*) To be more precise, 2 1/3 US cups of semolina is equal to 0.92603 pound. All figures are approximate.

US cups of semolina to pounds Chart

US cups of semolina to pounds
1.433 US cup of semolina = 0.569 pound
1.533 US cup of semolina = 0.608 pound
1.633 US cup of semolina = 0.648 pound
1.733 US cup of semolina = 0.688 pound
1.833 US cup of semolina = 0.728 pound
1.933 US cup of semolina = 0.767 pound
2.033 US cups of semolina = 0.807 pound
2.133 US cups of semolina = 0.847 pound
2.233 US cups of semolina = 0.886 pound
2.33 US cups of semolina = 0.926 pound
US cups of semolina to pounds
2.33 US cups of semolina = 0.926 pound
2.433 US cups of semolina = 0.966 pound
2.533 US cups of semolina = 1.01 pound
2.633 US cups of semolina = 1.05 pound
2.733 US cups of semolina = 1.08 pound
2.833 US cups of semolina = 1.12 pound
2.933 US cups of semolina = 1.16 pound
3.033 US cups of semolina = 1.2 pound
3.133 US cups of semolina = 1.24 pound
3.233 US cups of semolina = 1.28 pound

Note: some values may be rounded.

FAQs on semolina weight to volume conversion

2 1/3 US cups of semolina equals how many pounds?

2 1/3 US cups of semolina is equivalent 0.926 ( ~ 1) pound.

How much is 0.926 pound of semolina in US cups?

0.926 pound of semolina equals 2 1/3 ( ~ 2 1/4) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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