2 1/4 Cups of Semolina to Pounds Conversion

Question:
How many pounds of semolina in 2 1/4 US cups? How much are 2 1/4 cups of semolina in pounds?

The answer is:
2 1/4 US cups of semolina is equivalent to 0.893 ( ~ 1) pound(*)

Volume to 'Weight' Converter

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Results:

2 1/4 US cups of semolina equals 0.893 ( ~ 1) pound. (*)
(*) To be more precise, 2 1/4 US cups of semolina is equal to 0.89309 pound. All figures are approximate.

US cups of semolina to pounds Chart

US cups of semolina to pounds
1.35 US cup of semolina = 0.536 pound
1.45 US cup of semolina = 0.576 pound
1.55 US cup of semolina = 0.615 pound
1.65 US cup of semolina = 0.655 pound
1 3/4 US cup of semolina = 0.695 pound
1.85 US cup of semolina = 0.734 pound
1.95 US cup of semolina = 0.774 pound
2.05 US cups of semolina = 0.814 pound
2.15 US cups of semolina = 0.853 pound
2 1/4 US cups of semolina = 0.893 pound
US cups of semolina to pounds
2 1/4 US cups of semolina = 0.893 pound
2.35 US cups of semolina = 0.933 pound
2.45 US cups of semolina = 0.972 pound
2.55 US cups of semolina = 1.01 pound
2.65 US cups of semolina = 1.05 pound
2 3/4 US cups of semolina = 1.09 pound
2.85 US cups of semolina = 1.13 pound
2.95 US cups of semolina = 1.17 pound
3.05 US cups of semolina = 1.21 pound
3.15 US cups of semolina = 1.25 pound

Note: some values may be rounded.

FAQs on semolina weight to volume conversion

2 1/4 US cups of semolina equals how many pounds?

2 1/4 US cups of semolina is equivalent 0.893 ( ~ 1) pound.

How much is 0.893 pound of semolina in US cups?

0.893 pound of semolina equals 2 1/4 ( ~ 2 1/4) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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