2 2/3 Cups of Bulgur to Lb Conversion

Question:
How many pounds of bulgur in 2 2/3 US cups? How much are 2 2/3 cups of bulgur in lb?

The answer is:
2 2/3 US cups of bulgur is equivalent to 1.12 ( ~ 1) pounds^(*)

Volume to 'Weight' Converter

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Results: 2 2/3 US cups of bulgur equals 1.12 ( ~ 1) pounds. (*)
(*) To be more precise, 2 2/3 US cups of bulgur is equal to 1.117 pounds. All figures are approximate.

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US cups of bulgur to pounds Chart

US cups of bulgur to pounds
1.767 US cups of bulgur	=	0.74 pounds
1.867 US cups of bulgur	=	0.782 pounds
1.967 US cups of bulgur	=	0.824 pounds
2.067 US cups of bulgur	=	0.866 pounds
2.167 US cups of bulgur	=	0.908 pounds
2.267 US cups of bulgur	=	0.949 pounds
2.367 US cups of bulgur	=	0.991 pounds
2.467 US cups of bulgur	=	1.03 pounds
2.567 US cups of bulgur	=	1.08 pounds
2.67 US cups of bulgur	=	1.12 pounds

US cups of bulgur to pounds
2.67 US cups of bulgur	=	1.12 pounds
2.767 US cups of bulgur	=	1.16 pounds
2.867 US cups of bulgur	=	1.2 pounds
2.967 US cups of bulgur	=	1.24 pounds
3.067 US cups of bulgur	=	1.28 pounds
3.167 US cups of bulgur	=	1.33 pounds
3.267 US cups of bulgur	=	1.37 pounds
3.367 US cups of bulgur	=	1.41 pounds
3.467 US cups of bulgur	=	1.45 pounds
3.567 US cups of bulgur	=	1.49 pounds

Note: some values may be rounded.

FAQs on bulgur weight to volume conversion

2 2/3 US cups of bulgur equals how many pounds?

2 2/3 US cups of bulgur is equivalent 1.12 ( ~ 1) pounds.

How much is 1.12 pounds of bulgur in US cups?

1.12 pounds of bulgur equals 2 2/3 ( ~ 2 ³/₄) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.