2 2/3 Cups of Cocoa to Pounds Conversion

Question:
How many pounds of cocoa in 2 2/3 US cups? How much are 2 2/3 cups of cocoa in pounds?

The answer is:
2 2/3 US cups of cocoa is equivalent to 0.734 ( ~ 3/4) pounds(*)

Volume to 'Weight' Converter

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Results:

2 2/3 US cups of cocoa equals 0.734 ( ~ 3/4) pounds. (*)
(*) To be more precise, 2 2/3 US cups of cocoa is equal to 0.73449 pounds. All figures are approximate.

US cups of cocoa to pounds Chart

US cups of cocoa to pounds
1.767 US cups of cocoa = 0.487 pounds
1.867 US cups of cocoa = 0.514 pounds
1.967 US cups of cocoa = 0.542 pounds
2.067 US cups of cocoa = 0.569 pounds
2.167 US cups of cocoa = 0.597 pounds
2.267 US cups of cocoa = 0.624 pounds
2.367 US cups of cocoa = 0.652 pounds
2.467 US cups of cocoa = 0.679 pounds
2.567 US cups of cocoa = 0.707 pounds
2.67 US cups of cocoa = 0.734 pounds
US cups of cocoa to pounds
2.67 US cups of cocoa = 0.734 pounds
2.767 US cups of cocoa = 0.762 pounds
2.867 US cups of cocoa = 0.79 pounds
2.967 US cups of cocoa = 0.817 pounds
3.067 US cups of cocoa = 0.845 pounds
3.167 US cups of cocoa = 0.872 pounds
3.267 US cups of cocoa = 0.9 pounds
3.367 US cups of cocoa = 0.927 pounds
3.467 US cups of cocoa = 0.955 pounds
3.567 US cups of cocoa = 0.982 pounds

Note: some values may be rounded.

FAQs on cocoa weight to volume conversion

2 2/3 US cups of cocoa equals how many pounds?

2 2/3 US cups of cocoa is equivalent 0.734 ( ~ 3/4) pounds.

How much is 0.734 pounds of cocoa in US cups?

0.734 pounds of cocoa equals 2 2/3 ( ~ 2 3/4) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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