2 2/3 Cups of Dried Beans to Pounds Conversion

Question:
How many pounds of dried beans in 2 2/3 US cups? How much are 2 2/3 cups of dried beans in pounds?

The answer is:
2 2/3 US cups of dried beans is equivalent to 1.06 ( ~ 1) pound(*)

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Results:

2 2/3 US cups of dried beans equals 1.06 ( ~ 1) pound. (*)
(*) To be more precise, 2 2/3 US cups of dried beans is equal to 1.0586 pound. All figures are approximate.

US cups of dried beans to pounds Chart

US cups of dried beans to pounds
1.767 US cup of dried beans = 0.701 pound
1.867 US cup of dried beans = 0.741 pound
1.967 US cup of dried beans = 0.781 pound
2.067 US cups of dried beans = 0.82 pound
2.167 US cups of dried beans = 0.86 pound
2.267 US cups of dried beans = 0.9 pound
2.367 US cups of dried beans = 0.94 pound
2.467 US cups of dried beans = 0.979 pound
2.567 US cups of dried beans = 1.02 pound
2.67 US cups of dried beans = 1.06 pound
US cups of dried beans to pounds
2.67 US cups of dried beans = 1.06 pound
2.767 US cups of dried beans = 1.1 pound
2.867 US cups of dried beans = 1.14 pound
2.967 US cups of dried beans = 1.18 pound
3.067 US cups of dried beans = 1.22 pound
3.167 US cups of dried beans = 1.26 pound
3.267 US cups of dried beans = 1.3 pound
3.367 US cups of dried beans = 1.34 pound
3.467 US cups of dried beans = 1.38 pound
3.567 US cups of dried beans = 1.42 pound

Note: some values may be rounded.

FAQs on dried beans weight to volume conversion

2 2/3 US cups of dried beans equals how many pounds?

2 2/3 US cups of dried beans is equivalent 1.06 ( ~ 1) pound.

How much is 1.06 pound of dried beans in US cups?

1.06 pound of dried beans equals 2 2/3 ( ~ 2 3/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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