2 2/3 Cups of Dry Lentils to Lb Conversion

Question:
How many pounds of dry lentils in 2 2/3 US cups? How much are 2 2/3 cups of dry lentils in lb?

The answer is:
2 2/3 US cups of dry lentils is equivalent to 1.18 ( ~ 1 1/4) pound(*)

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Results:

2 2/3 US cups of dry lentils equals 1.18 ( ~ 1 1/4) pound. (*)
(*) To be more precise, 2 2/3 US cups of dry lentils is equal to 1.1755 pound. All figures are approximate.

US cups of dry lentils to pounds Chart

US cups of dry lentils to pounds
1.767 US cup of dry lentils = 0.779 pound
1.867 US cup of dry lentils = 0.823 pound
1.967 US cup of dry lentils = 0.867 pound
2.067 US cups of dry lentils = 0.911 pound
2.167 US cups of dry lentils = 0.955 pound
2.267 US cups of dry lentils = 0.999 pound
2.367 US cups of dry lentils = 1.04 pound
2.467 US cups of dry lentils = 1.09 pound
2.567 US cups of dry lentils = 1.13 pound
2.67 US cups of dry lentils = 1.18 pound
US cups of dry lentils to pounds
2.67 US cups of dry lentils = 1.18 pound
2.767 US cups of dry lentils = 1.22 pound
2.867 US cups of dry lentils = 1.26 pound
2.967 US cups of dry lentils = 1.31 pound
3.067 US cups of dry lentils = 1.35 pound
3.167 US cups of dry lentils = 1.4 pound
3.267 US cups of dry lentils = 1.44 pound
3.367 US cups of dry lentils = 1.48 pound
3.467 US cups of dry lentils = 1.53 pound
3.567 US cups of dry lentils = 1.57 pound

Note: some values may be rounded.

FAQs on dry lentils weight to volume conversion

2 2/3 US cups of dry lentils equals how many pounds?

2 2/3 US cups of dry lentils is equivalent 1.18 ( ~ 1 1/4) pound.

How much is 1.18 pound of dry lentils in US cups?

1.18 pound of dry lentils equals 2 2/3 ( ~ 2 3/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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