2 2/3 Cups of Ice Cream to Lb Conversion

Question:
How many pounds of ice cream in 2 2/3 US cups? How much are 2 2/3 cups of ice cream in lb?

The answer is:
2 2/3 US cups of ice cream is equivalent to 0.882 ( ~ 1) pounds(*)

Volume to 'Weight' Converter

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Results:

2 2/3 US cups of ice cream equals 0.882 ( ~ 1) pounds. (*)
(*) To be more precise, 2 2/3 US cups of ice cream is equal to 0.88194 pounds. All figures are approximate.

US cups of ice cream to pounds Chart

US cups of ice cream to pounds
1.767 US cups of ice cream = 0.584 pounds
1.867 US cups of ice cream = 0.617 pounds
1.967 US cups of ice cream = 0.65 pounds
2.067 US cups of ice cream = 0.684 pounds
2.167 US cups of ice cream = 0.717 pounds
2.267 US cups of ice cream = 0.75 pounds
2.367 US cups of ice cream = 0.783 pounds
2.467 US cups of ice cream = 0.816 pounds
2.567 US cups of ice cream = 0.849 pounds
2.67 US cups of ice cream = 0.882 pounds
US cups of ice cream to pounds
2.67 US cups of ice cream = 0.882 pounds
2.767 US cups of ice cream = 0.915 pounds
2.867 US cups of ice cream = 0.948 pounds
2.967 US cups of ice cream = 0.981 pounds
3.067 US cups of ice cream = 1.01 pounds
3.167 US cups of ice cream = 1.05 pounds
3.267 US cups of ice cream = 1.08 pounds
3.367 US cups of ice cream = 1.11 pounds
3.467 US cups of ice cream = 1.15 pounds
3.567 US cups of ice cream = 1.18 pounds

Note: some values may be rounded.

FAQs on ice cream weight to volume conversion

2 2/3 US cups of ice cream equals how many pounds?

2 2/3 US cups of ice cream is equivalent 0.882 ( ~ 1) pounds.

How much is 0.882 pounds of ice cream in US cups?

0.882 pounds of ice cream equals 2 2/3 ( ~ 2 3/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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