2 2/3 Cups of Raisins to Pounds Conversion

Question:
How many pounds of raisins in 2 2/3 US cups? How much are 2 2/3 cups of raisins in pounds?

The answer is:
2 2/3 US cups of raisins is equivalent to 0.935 ( ~ 1) pound(*)

Volume to 'Weight' Converter

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Results:

2 2/3 US cups of raisins equals 0.935 ( ~ 1) pound. (*)
(*) To be more precise, 2 2/3 US cups of raisins is equal to 0.9348 pound. All figures are approximate.

US cups of raisins to pounds Chart

US cups of raisins to pounds
1.767 US cup of raisins = 0.619 pound
1.867 US cup of raisins = 0.654 pound
1.967 US cup of raisins = 0.689 pound
2.067 US cups of raisins = 0.724 pound
2.167 US cups of raisins = 0.76 pound
2.267 US cups of raisins = 0.795 pound
2.367 US cups of raisins = 0.83 pound
2.467 US cups of raisins = 0.865 pound
2.567 US cups of raisins = 0.9 pound
2.67 US cups of raisins = 0.935 pound
US cups of raisins to pounds
2.67 US cups of raisins = 0.935 pound
2.767 US cups of raisins = 0.97 pound
2.867 US cups of raisins = 1 pound
2.967 US cups of raisins = 1.04 pound
3.067 US cups of raisins = 1.08 pound
3.167 US cups of raisins = 1.11 pound
3.267 US cups of raisins = 1.15 pound
3.367 US cups of raisins = 1.18 pound
3.467 US cups of raisins = 1.22 pound
3.567 US cups of raisins = 1.25 pound

Note: some values may be rounded.

FAQs on raisins weight to volume conversion

2 2/3 US cups of raisins equals how many pounds?

2 2/3 US cups of raisins is equivalent 0.935 ( ~ 1) pound.

How much is 0.935 pound of raisins in US cups?

0.935 pound of raisins equals 2 2/3 ( ~ 2 3/4) US cups.

Weight to Volume Conversions - Cooking Ingredients

References:

  1. Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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