2 2/3 Cups of Spring Onion to Grams Conversion

Question:
How many grams of spring onion in 2 2/3 US cups? How much are 2 2/3 cups of spring onion in grams?

The answer is:
2 2/3 US cups of spring onion is equivalent to 278 grams(*)

Volume to 'Weight' Converter

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Results:

2 2/3 US cups of spring onion equals 278 grams. (*)
(*) To be more precise, 2 2/3 US cups of spring onion is equal to 277.63 grams. All figures are approximate.

US cups of spring onion to grams Chart

US cups of spring onion to grams
1.767 US cup of spring onion = 184 grams
1.867 US cup of spring onion = 194 grams
1.967 US cup of spring onion = 205 grams
2.067 US cups of spring onion = 215 grams
2.167 US cups of spring onion = 226 grams
2.267 US cups of spring onion = 236 grams
2.367 US cups of spring onion = 246 grams
2.467 US cups of spring onion = 257 grams
2.567 US cups of spring onion = 267 grams
2.67 US cups of spring onion = 278 grams
US cups of spring onion to grams
2.67 US cups of spring onion = 278 grams
2.767 US cups of spring onion = 288 grams
2.867 US cups of spring onion = 298 grams
2.967 US cups of spring onion = 309 grams
3.067 US cups of spring onion = 319 grams
3.167 US cups of spring onion = 330 grams
3.267 US cups of spring onion = 340 grams
3.367 US cups of spring onion = 351 grams
3.467 US cups of spring onion = 361 grams
3.567 US cups of spring onion = 371 grams

Note: some values may be rounded.

FAQs on spring onion weight to volume conversion

2 2/3 US cups of spring onion equals how many grams?

2 2/3 US cups of spring onion is equivalent 278 grams.

How much is 278 grams of spring onion in US cups?

278 grams of spring onion equals 2 2/3 ( ~ 2 3/4) US cups.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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