20 Ml of Cocoa to Pounds Conversion

Question:
How many pounds of cocoa in 20 milliliters? How much are 20 ml of cocoa in pounds?

The answer is:
20 milliliters of cocoa is equivalent to 0.0233 pounds^(*)

Volume to 'Weight' Converter

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Results: 20 milliliters of cocoa equals 0.0233 pounds. (*)
(*) To be more precise, 20 milliliters of cocoa is equal to 0.023281 pounds. All figures are approximate.

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Milliliters of cocoa to pounds Chart

Milliliters of cocoa to pounds
11 milliliters of cocoa	=	0.0128 pounds
12 milliliters of cocoa	=	0.014 pounds
13 milliliters of cocoa	=	0.0151 pounds
14 milliliters of cocoa	=	0.0163 pounds
15 milliliters of cocoa	=	0.0175 pounds
16 milliliters of cocoa	=	0.0186 pounds
17 milliliters of cocoa	=	0.0198 pounds
18 milliliters of cocoa	=	0.021 pounds
19 milliliters of cocoa	=	0.0221 pounds
20 milliliters of cocoa	=	0.0233 pounds

Milliliters of cocoa to pounds
20 milliliters of cocoa	=	0.0233 pounds
21 milliliters of cocoa	=	0.0244 pounds
22 milliliters of cocoa	=	0.0256 pounds
23 milliliters of cocoa	=	0.0268 pounds
24 milliliters of cocoa	=	0.0279 pounds
25 milliliters of cocoa	=	0.0291 pounds
26 milliliters of cocoa	=	0.0303 pounds
27 milliliters of cocoa	=	0.0314 pounds
28 milliliters of cocoa	=	0.0326 pounds
29 milliliters of cocoa	=	0.0338 pounds

Note: some values may be rounded.

FAQs on cocoa weight to volume conversion

20 milliliters of cocoa equals how many pounds?

20 milliliters of cocoa is equivalent 0.0233 pounds.

How much is 0.0233 pounds of cocoa in milliliters?

0.0233 pounds of cocoa equals 20 milliliters.

Weight to Volume Conversions - Cooking Ingredients

References:

Density Database Version 2.0 - FAO

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.