20 Ml of Molasses to Pounds Conversion

Question:
How many pounds of molasses in 20 milliliters? How much are 20 ml of molasses in pounds?

The answer is:
20 milliliters of molasses is equivalent to 0.0522 pounds(*)

Volume to 'Weight' Converter

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Results:

20 milliliters of molasses equals 0.0522 pounds. (*)
(*) To be more precise, 20 milliliters of molasses is equal to 0.052161 pounds. All figures are approximate.

Milliliters of molasses to pounds Chart

Milliliters of molasses to pounds
11 milliliters of molasses = 0.0287 pounds
12 milliliters of molasses = 0.0313 pounds
13 milliliters of molasses = 0.0339 pounds
14 milliliters of molasses = 0.0365 pounds
15 milliliters of molasses = 0.0391 pounds
16 milliliters of molasses = 0.0417 pounds
17 milliliters of molasses = 0.0443 pounds
18 milliliters of molasses = 0.0469 pounds
19 milliliters of molasses = 0.0496 pounds
20 milliliters of molasses = 0.0522 pounds
Milliliters of molasses to pounds
20 milliliters of molasses = 0.0522 pounds
21 milliliters of molasses = 0.0548 pounds
22 milliliters of molasses = 0.0574 pounds
23 milliliters of molasses = 0.06 pounds
24 milliliters of molasses = 0.0626 pounds
25 milliliters of molasses = 0.0652 pounds
26 milliliters of molasses = 0.0678 pounds
27 milliliters of molasses = 0.0704 pounds
28 milliliters of molasses = 0.073 pounds
29 milliliters of molasses = 0.0756 pounds

Note: some values may be rounded.

FAQs on molasses weight to volume conversion

20 milliliters of molasses equals how many pounds?

20 milliliters of molasses is equivalent 0.0522 pounds.

How much is 0.0522 pounds of molasses in milliliters?

0.0522 pounds of molasses equals 20 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

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