20 Ml of Potato to Kg Conversion

Question:
How many kilograms of potato in 20 milliliters? How much are 20 ml of potato in kg?

The answer is:
20 milliliters of potato is equivalent to 0.0118 kilogram(*)

Volume to 'Weight' Converter

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Results:

20 milliliters of potato equals 0.0118 kilogram. (*)
(*) To be more precise, 20 milliliters of potato is equal to 0.0118 kilogram. All figures are approximate.

Milliliters of potato to kilograms Chart

Milliliters of potato to kilograms
11 milliliters of potato = 0.00649 kilogram
12 milliliters of potato = 0.00708 kilogram
13 milliliters of potato = 0.00767 kilogram
14 milliliters of potato = 0.00826 kilogram
15 milliliters of potato = 0.00885 kilogram
16 milliliters of potato = 0.00944 kilogram
17 milliliters of potato = 0.01 kilogram
18 milliliters of potato = 0.0106 kilogram
19 milliliters of potato = 0.0112 kilogram
20 milliliters of potato = 0.0118 kilogram
Milliliters of potato to kilograms
20 milliliters of potato = 0.0118 kilogram
21 milliliters of potato = 0.0124 kilogram
22 milliliters of potato = 0.013 kilogram
23 milliliters of potato = 0.0136 kilogram
24 milliliters of potato = 0.0142 kilogram
25 milliliters of potato = 0.0148 kilogram
26 milliliters of potato = 0.0153 kilogram
27 milliliters of potato = 0.0159 kilogram
28 milliliters of potato = 0.0165 kilogram
29 milliliters of potato = 0.0171 kilogram

Note: some values may be rounded.

FAQs on potato weight to volume conversion

20 milliliters of potato equals how many kilograms?

20 milliliters of potato is equivalent 0.0118 kilogram.

How much is 0.0118 kilogram of potato in milliliters?

0.0118 kilogram of potato equals 20 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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