20 Ml of Raisins to Kg Conversion

Question:
How many kilograms of raisins in 20 milliliters? How much are 20 ml of raisins in kg?

The answer is:
20 milliliters of raisins is equivalent to 0.0134 kilogram(*)

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Results:

20 milliliters of raisins equals 0.0134 kilogram. (*)
(*) To be more precise, 20 milliliters of raisins is equal to 0.01344 kilogram. All figures are approximate.

Milliliters of raisins to kilograms Chart

Milliliters of raisins to kilograms
11 milliliters of raisins = 0.00739 kilogram
12 milliliters of raisins = 0.00806 kilogram
13 milliliters of raisins = 0.00874 kilogram
14 milliliters of raisins = 0.00941 kilogram
15 milliliters of raisins = 0.0101 kilogram
16 milliliters of raisins = 0.0108 kilogram
17 milliliters of raisins = 0.0114 kilogram
18 milliliters of raisins = 0.0121 kilogram
19 milliliters of raisins = 0.0128 kilogram
20 milliliters of raisins = 0.0134 kilogram
Milliliters of raisins to kilograms
20 milliliters of raisins = 0.0134 kilogram
21 milliliters of raisins = 0.0141 kilogram
22 milliliters of raisins = 0.0148 kilogram
23 milliliters of raisins = 0.0155 kilogram
24 milliliters of raisins = 0.0161 kilogram
25 milliliters of raisins = 0.0168 kilogram
26 milliliters of raisins = 0.0175 kilogram
27 milliliters of raisins = 0.0181 kilogram
28 milliliters of raisins = 0.0188 kilogram
29 milliliters of raisins = 0.0195 kilogram

Note: some values may be rounded.

FAQs on raisins weight to volume conversion

20 milliliters of raisins equals how many kilograms?

20 milliliters of raisins is equivalent 0.0134 kilogram.

How much is 0.0134 kilogram of raisins in milliliters?

0.0134 kilogram of raisins equals 20 milliliters.

Notes on ingredient measurements

It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.

Disclaimer

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