20 Ml of Raisins to Pounds Conversion
Question:
How many pounds of raisins in 20 milliliters? How much are 20 ml of raisins in pounds?
The answer is:
20 milliliters of raisins is equivalent to 0.0296 pounds(*)
Volume to 'Weight' Converter
Milliliters of raisins to pounds Chart
Milliliters of raisins to pounds | ||
---|---|---|
11 milliliters of raisins | = | 0.0163 pounds |
12 milliliters of raisins | = | 0.0178 pounds |
13 milliliters of raisins | = | 0.0193 pounds |
14 milliliters of raisins | = | 0.0207 pounds |
15 milliliters of raisins | = | 0.0222 pounds |
16 milliliters of raisins | = | 0.0237 pounds |
17 milliliters of raisins | = | 0.0252 pounds |
18 milliliters of raisins | = | 0.0267 pounds |
19 milliliters of raisins | = | 0.0281 pounds |
20 milliliters of raisins | = | 0.0296 pounds |
Milliliters of raisins to pounds | ||
---|---|---|
20 milliliters of raisins | = | 0.0296 pounds |
21 milliliters of raisins | = | 0.0311 pounds |
22 milliliters of raisins | = | 0.0326 pounds |
23 milliliters of raisins | = | 0.0341 pounds |
24 milliliters of raisins | = | 0.0356 pounds |
25 milliliters of raisins | = | 0.037 pounds |
26 milliliters of raisins | = | 0.0385 pounds |
27 milliliters of raisins | = | 0.04 pounds |
28 milliliters of raisins | = | 0.0415 pounds |
29 milliliters of raisins | = | 0.043 pounds |
Note: some values may be rounded.
FAQs on raisins weight to volume conversion
20 milliliters of raisins equals how many pounds?
20 milliliters of raisins is equivalent 0.0296 pounds.
How much is 0.0296 pounds of raisins in milliliters?
0.0296 pounds of raisins equals 20 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.