200 Ml of Oil to Kg Conversion
Question:
How many kilograms of oil in 200 milliliters? How much are 200 ml of oil in kg?
The answer is:
200 milliliters of oil is equivalent to 0.189 kilograms(*)
Volume to 'Weight' Converter
Milliliters of oil to kilograms Chart
| Milliliters of oil to kilograms | ||
|---|---|---|
| 110 milliliters of oil | = | 0.104 kilograms |
| 120 milliliters of oil | = | 0.114 kilograms |
| 130 milliliters of oil | = | 0.123 kilograms |
| 140 milliliters of oil | = | 0.133 kilograms |
| 150 milliliters of oil | = | 0.142 kilograms |
| 160 milliliters of oil | = | 0.152 kilograms |
| 170 milliliters of oil | = | 0.161 kilograms |
| 180 milliliters of oil | = | 0.17 kilograms |
| 190 milliliters of oil | = | 0.18 kilograms |
| 200 milliliters of oil | = | 0.189 kilograms |
| Milliliters of oil to kilograms | ||
|---|---|---|
| 200 milliliters of oil | = | 0.189 kilograms |
| 210 milliliters of oil | = | 0.199 kilograms |
| 220 milliliters of oil | = | 0.208 kilograms |
| 230 milliliters of oil | = | 0.218 kilograms |
| 240 milliliters of oil | = | 0.227 kilograms |
| 250 milliliters of oil | = | 0.237 kilograms |
| 260 milliliters of oil | = | 0.246 kilograms |
| 270 milliliters of oil | = | 0.256 kilograms |
| 280 milliliters of oil | = | 0.265 kilograms |
| 290 milliliters of oil | = | 0.275 kilograms |
Note: some values may be rounded.
FAQs on oil weight to volume conversion
200 milliliters of oil equals how many kilograms?
200 milliliters of oil is equivalent 0.189 kilograms.
How much is 0.189 kilograms of oil in milliliters?
0.189 kilograms of oil equals 200 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.