225 Ml of Flour to Kg Conversion
Question:
How many kilograms of flour in 225 milliliters? How much are 225 ml of flour in kg?
The answer is:
225 milliliters of flour is equivalent to 0.119 kilogram(*)
Volume to 'Weight' Converter
Milliliters of flour to kilograms Chart
Milliliters of flour to kilograms | ||
---|---|---|
135 milliliters of flour | = | 0.0713 kilogram |
145 milliliters of flour | = | 0.0766 kilogram |
155 milliliters of flour | = | 0.0818 kilogram |
165 milliliters of flour | = | 0.0871 kilogram |
175 milliliters of flour | = | 0.0924 kilogram |
185 milliliters of flour | = | 0.0977 kilogram |
195 milliliters of flour | = | 0.103 kilogram |
205 milliliters of flour | = | 0.108 kilogram |
215 milliliters of flour | = | 0.114 kilogram |
225 milliliters of flour | = | 0.119 kilogram |
Milliliters of flour to kilograms | ||
---|---|---|
225 milliliters of flour | = | 0.119 kilogram |
235 milliliters of flour | = | 0.124 kilogram |
245 milliliters of flour | = | 0.129 kilogram |
255 milliliters of flour | = | 0.135 kilogram |
265 milliliters of flour | = | 0.14 kilogram |
275 milliliters of flour | = | 0.145 kilogram |
285 milliliters of flour | = | 0.15 kilogram |
295 milliliters of flour | = | 0.156 kilogram |
305 milliliters of flour | = | 0.161 kilogram |
315 milliliters of flour | = | 0.166 kilogram |
Note: some values may be rounded.
FAQs on flour weight to volume conversion
225 milliliters of flour equals how many kilograms?
225 milliliters of flour is equivalent 0.119 kilogram.
How much is 0.119 kilogram of flour in milliliters?
0.119 kilogram of flour equals 225 milliliters.
Weight to Volume Conversions - Cooking Ingredients
References:
Notes on ingredient measurements
It is a bit tricky to get an accurate food conversion since its characteristics change according to humidity, temperature, or how well packed the ingredient is. Ingredients that contain the terms sliced, minced, diced, crushed, chopped add uncertainties to the measurements. A good practice is to measure ingredients by weight, not by volume so that the error is decreased.
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